2.         If log 2925 = 3.46612 then find the values of log 29.25, log 2.925, log 0.002925 and log 292500.

Solution: Given, log 2925 = 3.46612

        Log 29.25 = log 2925 × 10 -2

                           = - 2 + log 2925

                            = -2 + 3.46612

                            = 1.46612

        Log 2.925 = log 2925 × 10 -3

                           = -3 + 3.46612

                           = 0.46612

        Log 0.002925 = log 2925 × 10-6

                                   = -6 + 3.46612

                                   = -3.46612

                                  = 3̅.46612

        Log 292500 = log 2925 × 102

                               = 2 + 3.46612

                               = 5.46612